Question-109642

Question Number 109642 by malwan last updated on 24/Aug/20

Answered by Dwaipayan Shikari last updated on 24/Aug/20

\int \frac{d x}{\sqrt{2 {t a n}^{2} θ + 2}} \frac{\sqrt{2}}{5} {s e c}^{2} θ d θ x = \frac{\sqrt{2}}{5} t a n θ

\frac{1}{5} \int s e c θ d θ

\frac{1}{5} l o g (s e c θ + t a n θ) = \frac{1}{5} l o g (\sqrt{\frac{25 x^{2} + 1}{2}} + \frac{5 x}{\sqrt{2}}) + C

Commented by malwan last updated on 24/Aug/20

g r e a t S i r

t h a n k y o u s o m u c h

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