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Question-44373




Question Number 44373 by jasno91 last updated on 28/Sep/18
Answered by tanmay.chaudhury50@gmail.com last updated on 28/Sep/18
a^2 =484  a=(√(484))      =(√(4×121))        =2×11  perimeter 4a  =4×22=88 m
$${a}^{\mathrm{2}} =\mathrm{484} \\ $$$${a}=\sqrt{\mathrm{484}} \\ $$$$\:\:\:\:=\sqrt{\mathrm{4}×\mathrm{121}}\: \\ $$$$\:\:\:\:\:=\mathrm{2}×\mathrm{11} \\ $$$${perimeter}\:\mathrm{4}{a} \\ $$$$=\mathrm{4}×\mathrm{22}=\mathrm{88}\:{m} \\ $$

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