Question Number 44537 by needhelp last updated on 01/Oct/18
Answered by $@ty@m last updated on 01/Oct/18
$${v}^{\mathrm{2}} ={u}^{\mathrm{2}} +\mathrm{2}{as} \\ $$$$\left(\mathrm{7}.\mathrm{10}\right)^{\mathrm{2}} =\mathrm{0}^{\mathrm{2}} +\mathrm{2}.{a}.\left(\mathrm{35}.\mathrm{4}\right) \\ $$$$\mathrm{50}.\mathrm{41}=\mathrm{70}.\mathrm{8}{a} \\ $$$${a}=\frac{\mathrm{50}.\mathrm{41}}{\mathrm{35}.\mathrm{4}} \\ $$$${a}=\mathrm{1}.\mathrm{42}\:{m}/{s}^{\mathrm{2}} \\ $$