Menu Close

Question-44808




Question Number 44808 by jasno91 last updated on 05/Oct/18
Commented by Kunal12588 last updated on 05/Oct/18
read some books
$${read}\:{some}\:{books} \\ $$
Answered by Kunal12588 last updated on 05/Oct/18
1) (82−18)(82+18)=6400  2) (128−72)(128+72)=56×200=11200  3)200^2 −3^2 =40000−9=39991  4)(((198−102)(198+102))/(96))=300  5)(15−0.3)(15+0.3)=225−0.09=224.91  6)(8.63+1.37)(8.63−1.37)=72.6
$$\left.\mathrm{1}\right)\:\left(\mathrm{82}−\mathrm{18}\right)\left(\mathrm{82}+\mathrm{18}\right)=\mathrm{6400} \\ $$$$\left.\mathrm{2}\right)\:\left(\mathrm{128}−\mathrm{72}\right)\left(\mathrm{128}+\mathrm{72}\right)=\mathrm{56}×\mathrm{200}=\mathrm{11200} \\ $$$$\left.\mathrm{3}\right)\mathrm{200}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} =\mathrm{40000}−\mathrm{9}=\mathrm{39991} \\ $$$$\left.\mathrm{4}\right)\frac{\left(\mathrm{198}−\mathrm{102}\right)\left(\mathrm{198}+\mathrm{102}\right)}{\mathrm{96}}=\mathrm{300} \\ $$$$\left.\mathrm{5}\right)\left(\mathrm{15}−\mathrm{0}.\mathrm{3}\right)\left(\mathrm{15}+\mathrm{0}.\mathrm{3}\right)=\mathrm{225}−\mathrm{0}.\mathrm{09}=\mathrm{224}.\mathrm{91} \\ $$$$\left.\mathrm{6}\right)\left(\mathrm{8}.\mathrm{63}+\mathrm{1}.\mathrm{37}\right)\left(\mathrm{8}.\mathrm{63}−\mathrm{1}.\mathrm{37}\right)=\mathrm{72}.\mathrm{6} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *