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Question-44810




Question Number 44810 by jasno91 last updated on 05/Oct/18
Answered by Kunal12588 last updated on 05/Oct/18
(6x)^2 −2(6x)(5y)+(5y)^2 =(6x−5y)^2   (4−1)^2 =9
$$\left(\mathrm{6}{x}\right)^{\mathrm{2}} −\mathrm{2}\left(\mathrm{6}{x}\right)\left(\mathrm{5}{y}\right)+\left(\mathrm{5}{y}\right)^{\mathrm{2}} =\left(\mathrm{6}{x}−\mathrm{5}{y}\right)^{\mathrm{2}} \\ $$$$\left(\mathrm{4}−\mathrm{1}\right)^{\mathrm{2}} =\mathrm{9} \\ $$

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