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Question-45561




Question Number 45561 by Sanjarbek last updated on 14/Oct/18
Commented by tanmay.chaudhury50@gmail.com last updated on 14/Oct/18
x=sinθ    dx=cosθdθ  ∫((cosθdθ)/( (√(cosθ))))  ∫(√(cosθ)) dθ  wait...
$${x}={sin}\theta\:\:\:\:{dx}={cos}\theta{d}\theta \\ $$$$\int\frac{{cos}\theta{d}\theta}{\:\sqrt{{cos}\theta}} \\ $$$$\int\sqrt{{cos}\theta}\:{d}\theta \\ $$$${wait}… \\ $$
Commented by arvinddayama01@gmail.com last updated on 14/Oct/18
x=cosθ  dx=−sinθdθ  −∫((sinθdθ)/( (√(sinθ))))  −∫(√(sinθ))dθ...
$${x}={cos}\theta \\ $$$${dx}=−{sin}\theta{d}\theta \\ $$$$−\int\frac{{sin}\theta{d}\theta}{\:\sqrt{{sin}\theta}} \\ $$$$−\int\sqrt{{sin}\theta}{d}\theta… \\ $$

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