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2cos-3pi-7-24-3a-72-where-a-27-4-147-4-




Question Number 45777 by habtetacke last updated on 16/Oct/18
2cos ((3π)/7)=((24+(√(3a)))/(72))where a=−27+4(√(147.4))
$$\mathrm{2cos}\:\frac{\mathrm{3}\pi}{\mathrm{7}}=\frac{\mathrm{24}+\sqrt{\mathrm{3}{a}}}{\mathrm{72}}{where}\:{a}=−\mathrm{27}+\mathrm{4}\sqrt{\mathrm{147}.\mathrm{4}} \\ $$
Commented by MJS last updated on 17/Oct/18
what′s the question?
$$\mathrm{what}'\mathrm{s}\:\mathrm{the}\:\mathrm{question}? \\ $$

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