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In-a-right-triangle-the-mid-point-of-the-hypotenuse-is-equidistant-from-all-the-three-vertices-of-the-triangle-




Question Number 4579 by Rasheed Soomro last updated on 08/Feb/16
In a right triangle, the mid-point of the  hypotenuse is equidistant from all the  three vertices of the triangle.
$${In}\:{a}\:{right}\:{triangle},\:{the}\:{mid}-{point}\:{of}\:{the} \\ $$$${hypotenuse}\:{is}\:{equidistant}\:{from}\:{all}\:{the} \\ $$$${three}\:{vertices}\:{of}\:{the}\:{triangle}. \\ $$
Commented by Yozzii last updated on 08/Feb/16
Prove this theorem?
$${Prove}\:{this}\:{theorem}? \\ $$
Commented by Rasheed Soomro last updated on 09/Feb/16
Yes.
$${Yes}. \\ $$
Answered by Yozzii last updated on 12/Feb/16
Commented by Yozzii last updated on 13/Feb/16
I should have specified that L   respresents the perpendicular bisector  of AB.
$${I}\:{should}\:{have}\:{specified}\:{that}\:{L}\: \\ $$$${respresents}\:{the}\:{perpendicular}\:{bisector} \\ $$$${of}\:{AB}. \\ $$

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