Question Number 111601 by A8;15: last updated on 04/Sep/20
Answered by bemath last updated on 04/Sep/20
$$\frac{\mathrm{7}.\mathrm{7}^{\mathrm{2004}} +\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}\:=\:\frac{\mathrm{8}.\mathrm{7}^{\mathrm{2004}} +\mathrm{1}}{\mathrm{7}^{\mathrm{2004}} +\mathrm{1}} \\ $$