Question Number 111788 by 675480065 last updated on 04/Sep/20
Answered by bemath last updated on 05/Sep/20
$$\:{a}\:=\:\mathrm{3}\:,\:{b}\:=\:\mathrm{4}\:;\:{c}\:=\:\mathrm{4} \\ $$$$\Leftrightarrow\:\mathrm{3}!\:\mathrm{3}!\:=\:\left(\mathrm{6}\right)^{\mathrm{2}} \:=\:\mathrm{36} \\ $$$$\Leftrightarrow\:\mathrm{3}!+\mathrm{3}!+\mathrm{4}!\:=\:\mathrm{6}+\mathrm{6}+\mathrm{24}\:=\:\mathrm{36}\: \\ $$