Question Number 177725 by Spillover last updated on 08/Oct/22
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{oxidation}\:\mathrm{number}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{underlined}\:\mathrm{element}\:\mathrm{in}\:\mathrm{the} \\ $$$$\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{K}\underline{\boldsymbol{\mathrm{Cl}}}\:\mathrm{O}_{\mathrm{3}} \\ $$$$\left(\mathrm{b}\right)\underline{\mathrm{S}O}_{\mathrm{3}} ^{\mathrm{2}−} \\ $$$$\left(\mathrm{c}\right)\mathrm{H}_{\mathrm{2}} \underline{\mathrm{S}O}_{\mathrm{4}} \\ $$$$\left(\mathrm{d}\right)\underline{\mathrm{Na}}\:\mathrm{H} \\ $$$$ \\ $$
Commented by Tawa11 last updated on 08/Oct/22
![(a) 1 + x − 6 = 0 x − 5 = 0 x = 5 [Cl = 5] (b) x − 6 = − 2 x = − 2 + 6 x = 4 [S = 4] (c) 2 + x − 8 = 0 x − 6 = 0 x = 6 [S = 6] (d) x − 1 = 0 x = 1 [Na = 1]](https://www.tinkutara.com/question/Q177758.png)
$$\left(\mathrm{a}\right)\:\:\:\:\:\mathrm{1}\:\:+\:\:\mathrm{x}\:\:−\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{5}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Cl}\:\:\:=\:\:\:\mathrm{5}\right] \\ $$$$ \\ $$$$\left(\mathrm{b}\right)\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:\:=\:\:\:\:−\:\:\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:\:=\:\:\:−\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{6} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{4}\right] \\ $$$$ \\ $$$$\left(\mathrm{c}\right)\:\:\:\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{8}\:\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{6}\right] \\ $$$$ \\ $$$$\left(\mathrm{d}\right)\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{1}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Na}\:\:\:=\:\:\:\mathrm{1}\right] \\ $$
Commented by Spillover last updated on 08/Oct/22
$$\mathrm{perfect}. \\ $$