Question Number 70168 by Askash last updated on 01/Oct/19
Commented by Askash last updated on 01/Oct/19
Please solve ����
Commented by MJS last updated on 01/Oct/19
$$\mathrm{zillions}\:\mathrm{of}\:\mathrm{possibilities} \\ $$$$\mathrm{if}\:\mathrm{we}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{what}'\mathrm{s}\:\mathrm{allowed}\:\mathrm{to}\:\mathrm{use}\:\mathrm{we} \\ $$$$\mathrm{cannot}\:\mathrm{solve}\:\mathrm{it} \\ $$
Commented by Askash last updated on 01/Oct/19
$$\boldsymbol{\mathcal{C}}{An}\:\boldsymbol{{Y}}{Ou}\:\boldsymbol{{S}}{oLve}\:{it}\:{by}\:{any}\:{easy} \\ $$$${method}? \\ $$$$ \\ $$$${If}\:{yes}\:{then}\:{please}\:{do}. \\ $$
Answered by MJS last updated on 01/Oct/19
$$\mathrm{ignoring}\:\mathrm{1},\:\mathrm{5} \\ $$$$\mathrm{2}{a}+\mathrm{3}{b}=\mathrm{13} \\ $$$$\mathrm{9}{a}+\mathrm{4}{b}=\mathrm{17} \\ $$$$\Rightarrow\:{a}=−\frac{\mathrm{1}}{\mathrm{19}}\wedge{b}=\frac{\mathrm{83}}{\mathrm{19}} \\ $$$$\mathrm{4}{a}+\mathrm{6}{b}=\mathrm{26} \\ $$