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400-2-100-2-




Question Number 47421 by 143jesus last updated on 09/Nov/18
(√(400^2 +100^2 =))
$$\sqrt{\mathrm{400}^{\mathrm{2}} +\mathrm{100}^{\mathrm{2}} =} \\ $$
Answered by MJS last updated on 09/Nov/18
=(√(100^2 ×4^2 +100^2 ×1^2 ))=(√(100^2 ×(4^2 +1^2 )))=  =(√(100^2 ))×(√(17))=100(√(17))≈412.31
$$=\sqrt{\mathrm{100}^{\mathrm{2}} ×\mathrm{4}^{\mathrm{2}} +\mathrm{100}^{\mathrm{2}} ×\mathrm{1}^{\mathrm{2}} }=\sqrt{\mathrm{100}^{\mathrm{2}} ×\left(\mathrm{4}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} \right)}= \\ $$$$=\sqrt{\mathrm{100}^{\mathrm{2}} }×\sqrt{\mathrm{17}}=\mathrm{100}\sqrt{\mathrm{17}}\approx\mathrm{412}.\mathrm{31} \\ $$

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