Question Number 179289 by Tawa11 last updated on 27/Oct/22
A refrigerator use 1200joules of work to jump 300j of heat from a cold reservoir of 275k to a hot reservoir at 320k.
1. What is the coefficient of performance.
2 the maximum efficiency of performance.
Answered by Acem last updated on 27/Oct/22
$$\mathrm{1}\bullet\:{K}=\:\frac{\mid{Q}_{{c}} \mid}{\mid{W}\mid}=\:\frac{\mathrm{300}}{\mathrm{1200}}=\:\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\mathrm{2}\bullet\:\:{K}_{{carnot}} =\:\frac{{T}_{{c}} }{{T}_{{H}} −{T}_{{c}} }\:=\:\mathrm{6}.\mathrm{1} \\ $$$$ \\ $$
Commented by Tawa11 last updated on 28/Oct/22
$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}. \\ $$
Commented by Acem last updated on 28/Oct/22
$${You}'{re}\:{welcome} \\ $$