Question Number 179654 by yaslm last updated on 31/Oct/22
Commented by CElcedricjunior last updated on 05/Nov/22
$$\mathrm{2}^{\mathrm{2}^{\mathrm{2}^{\mathrm{2}} } } =\mathrm{4}^{\boldsymbol{{x}}} =\mathrm{2}^{\mathrm{2}\boldsymbol{{x}}} \\ $$$$=>\mathrm{2}^{\mathrm{2}^{\mathrm{4}} } =\mathrm{2}^{\mathrm{2}\boldsymbol{{x}}} =>\mathrm{2}^{\mathrm{4}} =\mathrm{2}\boldsymbol{{x}}=>\boldsymbol{{x}}=\mathrm{2}^{\mathrm{4}} ×\mathrm{2}^{−\mathrm{1}} =\mathrm{2}^{\mathrm{3}} \\ $$$$=>\boldsymbol{\mathrm{x}}=\mathrm{2}^{\mathrm{3}} =\mathrm{8} \\ $$
Answered by malwan last updated on 31/Oct/22
$$\mathrm{8} \\ $$
Answered by mathlove last updated on 31/Oct/22
$$\mathrm{2}^{\mathrm{2}^{\mathrm{4}} } =\mathrm{2}^{\mathrm{2}{x}} \Rightarrow\mathrm{2}{x}=\mathrm{2}^{\mathrm{4}} \Rightarrow{x}=\mathrm{2}^{\mathrm{3}} =\mathrm{8} \\ $$