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ln-x-1-x-2-x-dx-




Question Number 180405 by cortano1 last updated on 12/Nov/22
   Ω = ∫ ((ln (x+1))/(x^2 +x)) dx =?
$$\:\:\:\Omega\:=\:\int\:\frac{\mathrm{ln}\:\left(\mathrm{x}+\mathrm{1}\right)}{\mathrm{x}^{\mathrm{2}} +\mathrm{x}}\:\mathrm{dx}\:=? \\ $$

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