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Question-181051




Question Number 181051 by mr W last updated on 20/Nov/22
Answered by a.lgnaoui last updated on 21/Nov/22
cote du carre bleu [CD]=b comme il  apparait dans (image)est  CD:prolongement de[ AC](AC)  [CD]=2×AC  AC=(√(2a^2 )) =a(√2)      Aire du csrre bleu :   A=(2×a(√2) )^2 =8a^2     Aire  A=8×A
$${cote}\:{du}\:{carre}\:{bleu}\:\left[{CD}\right]={b}\:{comme}\:{il} \\ $$$${apparait}\:{dans}\:\left({image}\right){est} \\ $$$${CD}:{prolongement}\:{de}\left[\:{AC}\right]\left({AC}\right) \\ $$$$\left[{CD}\right]=\mathrm{2}×{AC} \\ $$$${AC}=\sqrt{\mathrm{2}{a}^{\mathrm{2}} }\:={a}\sqrt{\mathrm{2}}\:\:\:\: \\ $$$${Aire}\:{du}\:{csrre}\:{bleu}\:: \\ $$$$\:{A}=\left(\mathrm{2}×{a}\sqrt{\mathrm{2}}\:\right)^{\mathrm{2}} =\mathrm{8}{a}^{\mathrm{2}} \\ $$$$\:\:{Aire}\:\:{A}=\mathrm{8}×{A} \\ $$$$ \\ $$
Commented by a.lgnaoui last updated on 21/Nov/22

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