Question Number 136054 by azadsir last updated on 18/Mar/21
Commented by mr W last updated on 18/Mar/21
$${a}=\mathrm{log}_{{x}} \:{xyz}=\frac{\mathrm{1}}{\mathrm{log}_{{xyz}} \:{x}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{a}}=\mathrm{log}_{{xyz}} \:{x} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}=\mathrm{log}_{{xyz}} \:{x}+\mathrm{log}_{{xyz}} \:{y}+\mathrm{log}_{{xyz}} \:{z} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{log}_{{xyz}} \:{xyz}=\mathrm{1} \\ $$
Commented by otchereabdullai@gmail.com last updated on 19/Mar/21
$$\mathrm{wow}! \\ $$