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find-the-value-of-I-0-ch-cos-2x-x-2-9-dx-and-J-0-cos-ch-2x-x-2-9-dx-




Question Number 116247 by mathmax by abdo last updated on 02/Oct/20
find the value of   I =∫_0 ^∞   ((ch(cos(2x)))/(x^2  +9))dx and  J =∫_0 ^∞  ((cos(ch(2x)))/(x^2  +9))dx
$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\:\mathrm{I}\:=\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{ch}\left(\mathrm{cos}\left(\mathrm{2x}\right)\right)}{\mathrm{x}^{\mathrm{2}} \:+\mathrm{9}}\mathrm{dx}\:\mathrm{and} \\ $$$$\mathrm{J}\:=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{cos}\left(\mathrm{ch}\left(\mathrm{2x}\right)\right)}{\mathrm{x}^{\mathrm{2}} \:+\mathrm{9}}\mathrm{dx} \\ $$

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