Question Number 182770 by mathlove last updated on 14/Dec/22
Answered by ARUNG_Brandon_MBU last updated on 14/Dec/22
$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\pi}{{n}}\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\mathrm{sin}\left(\frac{{k}\pi}{{n}}\right)=\pi\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{sin}\left(\pi{x}\right){dx}=\mathrm{2} \\ $$