Question Number 52038 by Gulay last updated on 02/Jan/19
$$\left(\mathrm{6x}+\mathrm{8}\right)+\mathrm{3}=\left(\mathrm{8x}−\mathrm{5}\right)−\mathrm{6}\:\:\: \\ $$$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 02/Jan/19
$$\mathrm{6}{x}+\mathrm{8}+\mathrm{3}=\mathrm{8}{x}−\mathrm{5}−\mathrm{6} \\ $$$$\mathrm{6}{x}+\mathrm{11}=\mathrm{8}{x}−\mathrm{11} \\ $$$$\mathrm{6}{x}−\mathrm{8}{x}=−\mathrm{11}−\mathrm{11} \\ $$$$−\mathrm{2}{x}=−\mathrm{22} \\ $$$${x}=\frac{\mathrm{22}}{\mathrm{2}}=\mathrm{11} \\ $$
Commented by Gulay last updated on 02/Jan/19
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir} \\ $$