Menu Close

Question-183185




Question Number 183185 by mnjuly1970 last updated on 22/Dec/22
Answered by mr W last updated on 23/Dec/22
Commented by mr W last updated on 23/Dec/22
OA=r_1 +r_2 −r_1 =r_2   OB=r_1 +r_2 −r_2 =r_1   OC=r_1 −r_2   (r_1 +R)^2 −(r_1 −R)^2 =(r_1 +r_2 −R)^2 −(r_1 −r_2 −R)^2   Rr_1 =(r_1 −R)r_2   ⇒R=((r_1 r_2 )/(r_1 +r_2 )) ✓
$${OA}={r}_{\mathrm{1}} +{r}_{\mathrm{2}} −{r}_{\mathrm{1}} ={r}_{\mathrm{2}} \\ $$$${OB}={r}_{\mathrm{1}} +{r}_{\mathrm{2}} −{r}_{\mathrm{2}} ={r}_{\mathrm{1}} \\ $$$${OC}={r}_{\mathrm{1}} −{r}_{\mathrm{2}} \\ $$$$\left({r}_{\mathrm{1}} +{R}\right)^{\mathrm{2}} −\left({r}_{\mathrm{1}} −{R}\right)^{\mathrm{2}} =\left({r}_{\mathrm{1}} +{r}_{\mathrm{2}} −{R}\right)^{\mathrm{2}} −\left({r}_{\mathrm{1}} −{r}_{\mathrm{2}} −{R}\right)^{\mathrm{2}} \\ $$$${Rr}_{\mathrm{1}} =\left({r}_{\mathrm{1}} −{R}\right){r}_{\mathrm{2}} \\ $$$$\Rightarrow{R}=\frac{{r}_{\mathrm{1}} {r}_{\mathrm{2}} }{{r}_{\mathrm{1}} +{r}_{\mathrm{2}} }\:\checkmark \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *