Question Number 52466 by Gulay last updated on 08/Jan/19
Commented by Gulay last updated on 08/Jan/19
$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$
Answered by math1967 last updated on 08/Jan/19
$$\left.\mathrm{2}{x}−{y}=\mathrm{12}\:…{i}\right) \\ $$$$\left.{x}+\mathrm{2}{y}=\mathrm{23}\:….{ii}\right) \\ $$$$\left.{i}\right)×\mathrm{2}\:\:\mathrm{4}{x}−\mathrm{2}{y}=\mathrm{24} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{x}+\mathrm{2}{y}=\mathrm{23} \\ $$$$−−−−−−−−−−− \\ $$$$\:\:\:\:\left({add}\right)\:\mathrm{5}{x}=\mathrm{47}\Rightarrow{x}=\frac{\mathrm{47}}{\mathrm{5}}=\mathrm{9}.\mathrm{4} \\ $$$$\:\:\:\:\therefore\mathrm{9}.\mathrm{4}+\mathrm{2}{y}=\mathrm{23}\:\:\therefore{y}=\frac{\mathrm{23}−\mathrm{9}.\mathrm{4}}{\mathrm{2}}=\mathrm{6}.\mathrm{8} \\ $$$$\:\:\:{x}=\mathrm{9}.\mathrm{4}\:{y}=\mathrm{6}.\mathrm{8}\:{ans} \\ $$$$ \\ $$