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Solve-sin-2x-2sin-2-x-3-cos-x-for-x-real-and-0-x-2pi-




Question Number 136268 by EDWIN88 last updated on 20/Mar/21
Solve sin (2x)−2sin^2 (x)=(√3) cos x for   x real and 0≤x≤2π
$$\mathrm{Solve}\:\mathrm{sin}\:\left(\mathrm{2x}\right)−\mathrm{2sin}\:^{\mathrm{2}} \left(\mathrm{x}\right)=\sqrt{\mathrm{3}}\:\mathrm{cos}\:\mathrm{x}\:\mathrm{for}\: \\ $$$$\mathrm{x}\:\mathrm{real}\:\mathrm{and}\:\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{2}\pi \\ $$

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