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Question-184356




Question Number 184356 by yaslm last updated on 05/Jan/23
Answered by greougoury555 last updated on 05/Jan/23
(i) x= 3y  (ii) 4x−60=3y+3  ⇒4x−60=x+3  ⇒ { ((x=21)),((y=7)) :}
$$\left({i}\right)\:{x}=\:\mathrm{3}{y} \\ $$$$\left({ii}\right)\:\mathrm{4}{x}−\mathrm{60}=\mathrm{3}{y}+\mathrm{3} \\ $$$$\Rightarrow\mathrm{4}{x}−\mathrm{60}={x}+\mathrm{3} \\ $$$$\Rightarrow\begin{cases}{{x}=\mathrm{21}}\\{{y}=\mathrm{7}}\end{cases} \\ $$$$ \\ $$
Answered by mr W last updated on 05/Jan/23
((x−(x−15))/(4y−(y+1)))=((15)/(3y−1))=(3/4) ⇒y=7  (x/(4×7))=(3/4) ⇒x=21
$$\frac{{x}−\left({x}−\mathrm{15}\right)}{\mathrm{4}{y}−\left({y}+\mathrm{1}\right)}=\frac{\mathrm{15}}{\mathrm{3}{y}−\mathrm{1}}=\frac{\mathrm{3}}{\mathrm{4}}\:\Rightarrow{y}=\mathrm{7} \\ $$$$\frac{{x}}{\mathrm{4}×\mathrm{7}}=\frac{\mathrm{3}}{\mathrm{4}}\:\Rightarrow{x}=\mathrm{21} \\ $$

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