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Question-118896




Question Number 118896 by bobhans last updated on 20/Oct/20
Answered by benjo_mathlover last updated on 20/Oct/20
 → (((2     b)),((b      2)) )  ((x),(y) ) =  (((ac^2 +c)),((  c−1)) )  →  ((x),(y) ) = (1/(4−b^2 ))  (((2   −b)),((−b   2)) )  (((ac^2 +c)),((   c−1)) )  → ((x),(y) ) = (1/(4−b^2 ))  (((2ac^2 +2c−bc+b)),((−abc^2 −bc+2c−2)) )
(2bb2)(xy)=(ac2+cc1)(xy)=14b2(2bb2)(ac2+cc1)(xy)=14b2(2ac2+2cbc+babc2bc+2c2)

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