Question Number 184435 by moh777 last updated on 06/Jan/23
![](https://www.tinkutara.com/question/28599.png)
Answered by CElcedricjunior last updated on 06/Jan/23
![lim_(x→0) ((arsinx−arctanx)/x)=0](https://www.tinkutara.com/question/Q184440.png)
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\boldsymbol{{arsinx}}−\boldsymbol{{arctanx}}}{\boldsymbol{{x}}}=\mathrm{0} \\ $$$$ \\ $$