Question Number 119576 by bemath last updated on 25/Oct/20
Answered by TANMAY PANACEA last updated on 25/Oct/20
$${x}=\frac{\mathrm{2}{m}}{\mathrm{3}}\:\:{y}=\frac{\mathrm{2}{n}}{\mathrm{3}}\:\:\:{z}=\frac{\mathrm{2}{k}}{\mathrm{3}} \\ $$$$\frac{\mathrm{4}{m}}{\mathrm{3}}+\mathrm{2}{n}+\frac{\mathrm{2}{k}}{\mathrm{3}}=\mathrm{22} \\ $$$$\mathrm{4}{m}+\mathrm{6}{n}+\mathrm{2}{k}=\mathrm{66} \\ $$$$\mathrm{4}\left(\mathrm{13}−{k}\right)+\mathrm{6}{n}+\mathrm{2}{k}=\mathrm{66} \\ $$$$\mathrm{6}{n}−\mathrm{2}{k}=\mathrm{66}−\mathrm{52}=\mathrm{14} \\ $$$$\mathrm{3}{n}−{k}=\mathrm{7} \\ $$
Answered by bemath last updated on 25/Oct/20
