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Question-119755




Question Number 119755 by zakirullah last updated on 26/Oct/20
Commented by bobhans last updated on 26/Oct/20
a×b =  determinant (((3    −6         5)),((2     −1       4)))= −19i−2j+9k  b×c =  determinant (((2     −1       4)),((1         1      −1)))= −3i+6j+3k
$$\boldsymbol{{a}}×\boldsymbol{{b}}\:=\:\begin{vmatrix}{\mathrm{3}\:\:\:\:−\mathrm{6}\:\:\:\:\:\:\:\:\:\mathrm{5}}\\{\mathrm{2}\:\:\:\:\:−\mathrm{1}\:\:\:\:\:\:\:\mathrm{4}}\end{vmatrix}=\:−\mathrm{19}\boldsymbol{{i}}−\mathrm{2}\boldsymbol{{j}}+\mathrm{9}\boldsymbol{{k}} \\ $$$$\boldsymbol{{b}}×\boldsymbol{{c}}\:=\:\begin{vmatrix}{\mathrm{2}\:\:\:\:\:−\mathrm{1}\:\:\:\:\:\:\:\mathrm{4}}\\{\mathrm{1}\:\:\:\:\:\:\:\:\:\mathrm{1}\:\:\:\:\:\:−\mathrm{1}}\end{vmatrix}=\:−\mathrm{3}\boldsymbol{{i}}+\mathrm{6}\boldsymbol{{j}}+\mathrm{3}\boldsymbol{{k}} \\ $$$$ \\ $$
Commented by zakirullah last updated on 27/Oct/20
great!
$$\boldsymbol{{great}}! \\ $$

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