Question Number 185678 by Mingma last updated on 25/Jan/23
Answered by Frix last updated on 25/Jan/23
$${y}^{\mathrm{3}} +\mathrm{2}{y}−{x}=\mathrm{0} \\ $$$$\mathrm{Cardano}'\mathrm{s}\:\mathrm{Formula} \\ $$$${y}=\sqrt[{\mathrm{3}}]{\frac{{x}}{\mathrm{2}}+\sqrt{\frac{{x}^{\mathrm{2}} }{\mathrm{4}}+\frac{\mathrm{8}}{\mathrm{27}}}}−\sqrt[{\mathrm{3}}]{−\frac{{x}}{\mathrm{2}}+\sqrt{\frac{{x}^{\mathrm{2}} }{\mathrm{4}}+\frac{\mathrm{8}}{\mathrm{27}}}} \\ $$