Question Number 54827 by problem solverd last updated on 12/Feb/19
$$\mathrm{logx}^{\mathrm{2}} +\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}−\mathrm{6}\right)=\mathrm{3} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{x} \\ $$
logx-2-log-2-x-6-3-solve-for-x-