Question Number 55052 by Tawa1 last updated on 16/Feb/19
Commented by mr W last updated on 17/Feb/19
$$\mid\overset{\rightarrow} {\boldsymbol{{S}}}−\overset{\rightarrow} {\boldsymbol{{T}}}\mid=\mid{AB}\mid>\mathrm{0} \\ $$$$\mid{AB}_{\mathrm{1}} \mid=\mathrm{1}{m} \\ $$$$\mid{AB}_{\mathrm{2}} \mid=\sqrt{\mathrm{3}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} }=\mathrm{5}{m} \\ $$$$\mid{AB}_{\mathrm{3}} \mid=\mathrm{3}+\mathrm{4}=\mathrm{7}{m} \\ $$$$\Rightarrow\left({ii}\right),\:\left({iii}\right),\:\left({iv}\right)\:{are}\:{correct}. \\ $$
Commented by mr W last updated on 17/Feb/19
Commented by Tawa1 last updated on 17/Feb/19
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir} \\ $$