Question Number 445 by 123456 last updated on 05/Jan/15
![0≤∣f(x)∣≤∣g(x)∣ ∫g(x)−f(x) dx≤∫f(x)+g(x) dx ?](https://www.tinkutara.com/question/Q445.png)
$$\mathrm{0}\leqslant\mid{f}\left({x}\right)\mid\leqslant\mid{g}\left({x}\right)\mid \\ $$$$\int{g}\left({x}\right)−{f}\left({x}\right)\:{dx}\leqslant\int{f}\left({x}\right)+{g}\left({x}\right)\:{dx}\:\:? \\ $$
Commented by prakash jain last updated on 05/Jan/15
![f(x)=−1 g(x)=1 ∣f(x)∣=1 ∣g(x)∣=1 g(x)−f(x)=2 f(x)+g(x)=0](https://www.tinkutara.com/question/Q446.png)
$${f}\left({x}\right)=−\mathrm{1} \\ $$$${g}\left({x}\right)=\mathrm{1} \\ $$$$\mid{f}\left({x}\right)\mid=\mathrm{1} \\ $$$$\mid{g}\left({x}\right)\mid=\mathrm{1} \\ $$$${g}\left({x}\right)−{f}\left({x}\right)=\mathrm{2} \\ $$$${f}\left({x}\right)+{g}\left({x}\right)=\mathrm{0} \\ $$