Question Number 186489 by Mingma last updated on 05/Feb/23
Answered by Frix last updated on 06/Feb/23
$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} =\mathrm{1981}^{\mathrm{2}} =\mathrm{7}^{\mathrm{2}} ×\mathrm{283}^{\mathrm{2}} \\ $$$$\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} =\mathrm{7}^{\mathrm{2}} \\ $$$$\left(\mathrm{2}×\mathrm{283}\right)^{\mathrm{2}} +\left(\mathrm{3}×\mathrm{283}\right)^{\mathrm{2}} +\left(\mathrm{6}×\mathrm{283}\right)^{\mathrm{2}} =\left(\mathrm{7}×\mathrm{283}\right)^{\mathrm{2}} \\ $$$$\mathrm{566}^{\mathrm{2}} +\mathrm{849}^{\mathrm{2}} +\mathrm{1698}^{\mathrm{2}} =\mathrm{1981}^{\mathrm{2}} \\ $$