Question Number 186691 by 073 last updated on 08/Feb/23
Answered by Ar Brandon last updated on 08/Feb/23
$$\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}{x}\right)=\frac{\pi}{\mathrm{2}}−\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{tan}{x}\right)=\frac{\pi}{\mathrm{2}}−{x} \\ $$$$\int\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}{x}\right){dx}=\int\left(\frac{\pi}{\mathrm{2}}−{x}\right){dx} \\ $$