Question Number 55860 by Easyman32 last updated on 05/Mar/19
Answered by tanmay.chaudhury50@gmail.com last updated on 05/Mar/19
$${jones}\:{probablity}\:{of}\:{winning}={a} \\ $$$${john}\:{probablity}\:{of}\:{winning}=\mathrm{3}{a} \\ $$$${david}….=\mathrm{2}×\mathrm{3}{a}=\mathrm{6}{a} \\ $$$${a}+\mathrm{3}{a}+\mathrm{6}{a}=\mathrm{1} \\ $$$${a}=\frac{\mathrm{1}}{\mathrm{10}} \\ $$$${john}\:{probablity}=\frac{\mathrm{3}}{\mathrm{10}} \\ $$$${pls}\:{check}… \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 05/Mar/19
$$\left.\mathrm{33}\right){pasd}\:{in}\:{math}={p} \\ $$$${fail}\:{in}\:{math}=\mathrm{1}−{p} \\ $$$${pass}\:{in}\:{physics}={q} \\ $$$${fail}\:{in}\:{physics}=\mathrm{1}−{q} \\ $$$${pass}\:{in}\:{math}\:{but}\:{fail}\:{in}\:{physics}={p}\left(\mathrm{1}−{q}\right) \\ $$