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a-x-b-y-c-z-1-3-a-2b-c-2-and-2y-3z-1-x-how-is-solution-




Question Number 187020 by mustafazaheen last updated on 12/Feb/23
(a/x)=(b/y)=(c/z)=(1/3)    ,a−2b+c=2  and  2y−3z=1    x=?  how is solution
$$\frac{{a}}{{x}}=\frac{{b}}{{y}}=\frac{{c}}{{z}}=\frac{\mathrm{1}}{\mathrm{3}}\:\:\:\:,{a}−\mathrm{2}{b}+{c}=\mathrm{2}\:\:{and}\:\:\mathrm{2}{y}−\mathrm{3}{z}=\mathrm{1}\:\:\:\:{x}=? \\ $$$${how}\:{is}\:{solution} \\ $$
Commented by mr W last updated on 12/Feb/23
you can not determine x and other  unknowns!  there are 6 unknowns, but you have  only 5 equations, so you can not  solve.  question is wrong!
$${you}\:{can}\:{not}\:{determine}\:{x}\:{and}\:{other} \\ $$$${unknowns}! \\ $$$${there}\:{are}\:\mathrm{6}\:{unknowns},\:{but}\:{you}\:{have} \\ $$$${only}\:\mathrm{5}\:{equations},\:{so}\:{you}\:{can}\:{not} \\ $$$${solve}. \\ $$$${question}\:{is}\:{wrong}! \\ $$

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