Question Number 187191 by 073 last updated on 14/Feb/23
Commented by Rasheed.Sindhi last updated on 14/Feb/23
$${You}\:{don}'{t}\:{deserve}\:{solution}\:{because} \\ $$$${you}\:{don}'{t}\:{give}\:{any}\:{feedback}. \\ $$
Commented by 073 last updated on 14/Feb/23
$$\mathrm{please}\:\mathrm{solve}\:\mathrm{it}\: \\ $$$$ \\ $$
Answered by aba last updated on 14/Feb/23
$$\mathrm{2}^{−\mathrm{1}} =\mathrm{2}^{−\mathrm{1}} \ast\mathrm{e}=\mathrm{2}^{−\mathrm{1}} \ast\left(\mathrm{2}\ast\mathrm{2}^{−\mathrm{1}} \right)=\mathrm{2}^{−\mathrm{1}} \ast\left(\frac{\mathrm{2}×\mathrm{2}^{−\mathrm{1}} }{\mathrm{4}}\right)=\mathrm{2}^{−\mathrm{1}} \ast\frac{\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{2}^{−\mathrm{1}} ×\frac{\mathrm{1}}{\mathrm{4}}}{\mathrm{4}}=\frac{\mathrm{1}}{\mathrm{32}} \\ $$
Commented by 073 last updated on 15/Feb/23
$$ \\ $$
Answered by mr W last updated on 15/Feb/23
$${x}\ast{y}=\frac{{xy}}{\mathrm{4}} \\ $$$${x}\ast{e}=\frac{{xe}}{\mathrm{4}}={x}\:\Rightarrow{e}=\mathrm{4} \\ $$$${x}\ast{x}^{−\mathrm{1}} =\frac{{x}\centerdot{x}^{−\mathrm{1}} }{\mathrm{4}}={e}=\mathrm{4}\: \\ $$$$\Rightarrow{x}\centerdot{x}^{−\mathrm{1}} =\mathrm{4}×\mathrm{4}=\mathrm{16}\:\Rightarrow{x}^{−\mathrm{1}} =\frac{\mathrm{16}}{{x}} \\ $$$$\Rightarrow\mathrm{2}^{−\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{2}}=\mathrm{8} \\ $$
Commented by 073 last updated on 15/Feb/23
$$\mathrm{thanks}\:\mathrm{alot} \\ $$