Question Number 122540 by help last updated on 18/Nov/20
Commented by help last updated on 18/Nov/20
$${find}\:{the}\:{perimeter}\:{of}\:{the}\:{shape} \\ $$
Answered by Olaf last updated on 18/Nov/20
$$\mathrm{above}\::\:\mathrm{4}.\mathrm{7}+\mathrm{3}+\frac{\pi}{\mathrm{2}}\left(\mathrm{11}.\mathrm{2}−\mathrm{4}.\mathrm{7}−\mathrm{3}\right) \\ $$$$\mathrm{right}\::\:\mathrm{3}.\mathrm{5}+\mathrm{3}.\mathrm{5}+\frac{\pi}{\mathrm{2}}\left(\mathrm{14}−\mathrm{3}.\mathrm{5}−\mathrm{3}.\mathrm{5}\right) \\ $$$$\mathrm{below}\::\:\frac{\pi}{\mathrm{2}}×\mathrm{11}.\mathrm{2} \\ $$$$\mathrm{left}\::\:\mathrm{14} \\ $$$$ \\ $$$$\mathrm{total}\::\:\left(\mathrm{7}.\mathrm{7}+\mathrm{1}.\mathrm{75}\pi\right)+\left(\mathrm{7}+\mathrm{3}.\mathrm{5}\pi\right)+\left(\mathrm{5}.\mathrm{6}\pi\right)+\mathrm{14} \\ $$$$=\:\mathrm{28}.\mathrm{7}+\mathrm{10}.\mathrm{85}\pi \\ $$