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Question-5632




Question Number 5632 by sanusihammed last updated on 23/May/16
Answered by FilupSmith last updated on 23/May/16
Exterior angles = 360^o   2x+3x+x−40+x+10+x−60=360  8x−90=360  8x=450  x=((450)/8)
$$\mathrm{Exterior}\:\mathrm{angles}\:=\:\mathrm{360}^{\mathrm{o}} \\ $$$$\mathrm{2}{x}+\mathrm{3}{x}+{x}−\mathrm{40}+{x}+\mathrm{10}+{x}−\mathrm{60}=\mathrm{360} \\ $$$$\mathrm{8}{x}−\mathrm{90}=\mathrm{360} \\ $$$$\mathrm{8}{x}=\mathrm{450} \\ $$$${x}=\frac{\mathrm{450}}{\mathrm{8}} \\ $$
Commented by sanusihammed last updated on 23/May/16
Thanks so much
$${Thanks}\:{so}\:{much} \\ $$

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