Question Number 122954 by mr W last updated on 21/Nov/20
Commented by Dwaipayan Shikari last updated on 21/Nov/20
$${Infinitely}\:\:{many}\:{answers}\:{sir}! \\ $$$${If}\:{they}\:{are}\:{in}\:{a}\:{relation}\:\:{C}=\mathrm{1}+\left({n}−\mathrm{1}\right) \\ $$$${then}\:\mathrm{12}\:{will}\:{cost}\:\mathrm{12}\:\$\:\:\:\left({for}\:{the}\:{people}\:{who}…..\right) \\ $$$${If}\:{they}\:{are}\:{in}\:{a}\:{relation} \\ $$$${n}+\left({n}−\mathrm{1}\right)\left({n}−\mathrm{2}\right)\left({n}−\mathrm{3}\right)…\left({n}−\mathrm{11}\right) \\ $$$${If}\:{n}=\mathrm{12} \\ $$$$\left.{then}\:{price}\:{will}\:{be}\:\mathrm{12}+\mathrm{11}!\:\$\:\:\:\::\right) \\ $$$$…… \\ $$
Commented by prakash jain last updated on 22/Nov/20
$$\mathrm{Information}\:\mathrm{about}\:\mathrm{2}\:\mathrm{and}\:\mathrm{11}\:\mathrm{is} \\ $$$$\mathrm{redundant}. \\ $$$$\mathrm{12}=\:\mathrm{12}\:\mathrm{times}\:\mathrm{ONE} \\ $$$$\mathrm{So}\:\mathrm{12}\:\mathrm{will}\:\mathrm{cost}\:\$\mathrm{12}. \\ $$
Commented by mr W last updated on 22/Nov/20
$${an}\:{other}\:{possibility}: \\ $$$${say}\:{a}\:{letter}\:\boldsymbol{{O}}\:{costs}\:{o}\:\$,\:{a}\:{letter}\:\boldsymbol{{N}} \\ $$$${costs}\:{n}\:\$,\:{etc}. \\ $$$${o}+{n}+{e}=\mathrm{1}\:\:\:…\left({i}\right) \\ $$$${t}+{w}+{o}=\mathrm{2}\:\:\:…\left({ii}\right) \\ $$$$\mathrm{3}{e}+{l}+{v}+{n}=\mathrm{11}\:\:\:…\left({iii}\right) \\ $$$$\left({iii}\right)+\left({ii}\right)−\left({i}\right): \\ $$$$\mathrm{2}{e}+{l}+{v}+{t}+{w}=\mathrm{12}\:\:\:…\left({iv}\right) \\ $$$$ \\ $$$$\boldsymbol{{TWELVE}}\:{costs}\:\mathrm{2}{e}+{t}+{w}+{l}+{v},\:{that} \\ $$$${is}\:\mathrm{12}\:\$\:{from}\:\left({iv}\right). \\ $$