Question Number 188901 by Mingma last updated on 08/Mar/23
Answered by Frix last updated on 08/Mar/23
$${AB}=\sqrt{\mathrm{8}^{\mathrm{2}} +\left(\mathrm{10}−\mathrm{4}\right)^{\mathrm{2}} }=\mathrm{10} \\ $$$${BC}=\sqrt{\mathrm{8}^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} }=\mathrm{2}\sqrt{\mathrm{41}} \\ $$$${R}_{{ABC}} =\frac{\mathrm{5}\sqrt{\mathrm{41}}}{\mathrm{4}} \\ $$$$\Rightarrow\:\mathrm{Answer}\:\mathrm{is}\:\frac{\mathrm{1025}\pi}{\mathrm{16}}−\mathrm{56} \\ $$
Commented by Mingma last updated on 08/Mar/23
Excellent!