Question Number 58027 by problem solverd last updated on 16/Apr/19
Answered by tanmay last updated on 16/Apr/19
$$\mathrm{7}{xy}^{\mathrm{6}} \frac{{dy}}{{dx}}+{y}^{\mathrm{7}} −{x}^{\mathrm{5}} \frac{{dy}}{{dx}}−\mathrm{5}{x}^{\mathrm{4}} {y}−\frac{\mathrm{5}}{{x}^{\mathrm{2}} }=\mathrm{4}{y}+\mathrm{4}{x}\frac{{dy}}{{dx}} \\ $$$$\frac{{dy}}{{dx}}\left(\mathrm{7}{xy}^{\mathrm{6}} −{x}^{\mathrm{5}} −\mathrm{4}{x}\right)=\mathrm{4}{y}+\frac{\mathrm{5}}{{x}^{\mathrm{2}} }−{y}^{\mathrm{7}} +\mathrm{5}{x}^{\mathrm{4}} {y} \\ $$$$\frac{{dy}}{{dx}}=\frac{\mathrm{4}{y}−{y}^{\mathrm{7}} +\mathrm{5}{x}^{\mathrm{4}} {y}+\frac{\mathrm{5}}{{x}^{\mathrm{2}} }}{\mathrm{7}{xy}^{\mathrm{6}} −{x}^{\mathrm{5}} −\mathrm{4}{x}} \\ $$
Commented by problem solverd last updated on 16/Apr/19
$${thanx}\:{alot}\:{sir} \\ $$
Commented by tanmay last updated on 16/Apr/19
$${most}\:{welcome} \\ $$