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Question-58027




Question Number 58027 by problem solverd last updated on 16/Apr/19
Answered by tanmay last updated on 16/Apr/19
7xy^6 (dy/dx)+y^7 −x^5 (dy/dx)−5x^4 y−(5/x^2 )=4y+4x(dy/dx)  (dy/dx)(7xy^6 −x^5 −4x)=4y+(5/x^2 )−y^7 +5x^4 y  (dy/dx)=((4y−y^7 +5x^4 y+(5/x^2 ))/(7xy^6 −x^5 −4x))
$$\mathrm{7}{xy}^{\mathrm{6}} \frac{{dy}}{{dx}}+{y}^{\mathrm{7}} −{x}^{\mathrm{5}} \frac{{dy}}{{dx}}−\mathrm{5}{x}^{\mathrm{4}} {y}−\frac{\mathrm{5}}{{x}^{\mathrm{2}} }=\mathrm{4}{y}+\mathrm{4}{x}\frac{{dy}}{{dx}} \\ $$$$\frac{{dy}}{{dx}}\left(\mathrm{7}{xy}^{\mathrm{6}} −{x}^{\mathrm{5}} −\mathrm{4}{x}\right)=\mathrm{4}{y}+\frac{\mathrm{5}}{{x}^{\mathrm{2}} }−{y}^{\mathrm{7}} +\mathrm{5}{x}^{\mathrm{4}} {y} \\ $$$$\frac{{dy}}{{dx}}=\frac{\mathrm{4}{y}−{y}^{\mathrm{7}} +\mathrm{5}{x}^{\mathrm{4}} {y}+\frac{\mathrm{5}}{{x}^{\mathrm{2}} }}{\mathrm{7}{xy}^{\mathrm{6}} −{x}^{\mathrm{5}} −\mathrm{4}{x}} \\ $$
Commented by problem solverd last updated on 16/Apr/19
thanx alot sir
$${thanx}\:{alot}\:{sir} \\ $$
Commented by tanmay last updated on 16/Apr/19
most welcome
$${most}\:{welcome} \\ $$

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