Question Number 58050 by Aditya789 last updated on 17/Apr/19
Answered by tanmay last updated on 17/Apr/19
$${D}_{\mathrm{1}} =\left\{\mathrm{1}\:\mathrm{2}\:\mathrm{3}\:\mathrm{4}\:\mathrm{5}\:\mathrm{6}\:\right\} \\ $$$$\:\:{D}_{\mathrm{2}} =\left\{\mathrm{1}\:\mathrm{2}\:\:\mathrm{3}\:\mathrm{4}\:\mathrm{5}\:\mathrm{6}\right\} \\ $$$$\:\:{D}_{\mathrm{3}} \:=\left\{\mathrm{1}\:\mathrm{2}\:\mathrm{3}\:\mathrm{4}\:\mathrm{5}\:\mathrm{6}\right\} \\ $$$${D}_{\mathrm{1}} =\mathrm{1}\:\left({say}\right)\rightarrow\mathrm{6}{C}_{\mathrm{1}} \\ $$$${D}_{\mathrm{2}} =\left\{\mathrm{2}\:\mathrm{3}\:\mathrm{4}\:\mathrm{5}\:\mathrm{6}\right\}{any}\:{one}\:{face}\:\rightarrow\mathrm{5}_{{C}_{\mathrm{1}} } \\ $$$${say}\:{D}_{\mathrm{2}} =\mathrm{2}\:\rightarrow\mathrm{4}{C}_{\mathrm{1}} \\ $$$$\:{p}\left({A}\right)=\frac{\mathrm{6}×\mathrm{5}×\mathrm{4}}{\mathrm{6}×\mathrm{6}×\mathrm{6}}=\frac{\mathrm{5}}{\mathrm{9}} \\ $$$${plz}\:{check}\:{is}\:{it}?{correct}.. \\ $$