Question Number 189169 by mr W last updated on 12/Mar/23
Commented by mr W last updated on 12/Mar/23
$${find}\:{the}\:{shaded}\:{area}=? \\ $$
Commented by Ari last updated on 12/Mar/23
$${why}\:{are}\:{the}\:{areas}\:{of}\:{tow}\:{isosceles} \\ $$$${triangles}\:{equal}? \\ $$
Commented by HeferH last updated on 13/Mar/23
$$\mathrm{sorry}\:\mathrm{i}\:\mathrm{dont}\:\mathrm{see}\:\mathrm{any}\:\mathrm{isosceles}\:\mathrm{triangle} \\ $$
Commented by HeferH last updated on 13/Mar/23
$$\mathrm{if}\:\mathrm{you}\:\mathrm{meant}\:\mathrm{the}\:\mathrm{triangles}\:\mathrm{of}\:\mathrm{area}\:\mathrm{x}: \\ $$$$\:\mathrm{same}\:\mathrm{height},\:\mathrm{same}\:\mathrm{base}\:\Rightarrow\mathrm{same}\:\mathrm{area} \\ $$
Answered by HeferH last updated on 12/Mar/23
Commented by HeferH last updated on 12/Mar/23
$${x}^{\mathrm{2}} \:=\:\mathrm{2}\centerdot\mathrm{8} \\ $$$${x}\:=\:\mathrm{4} \\ $$$${Rectangle}\:{area}\:=\:\mathrm{2}\left(\mathrm{4}\:+\:\mathrm{8}\right)\:=\:\mathrm{24} \\ $$$${Yellow}\:=\:\mathrm{24}\:−\:\left(\mathrm{6}\:+\mathrm{8}\:+\mathrm{2}\right)\:=\:\mathrm{8}{u}^{\mathrm{2}} \\ $$
Commented by mr W last updated on 12/Mar/23
$${great}! \\ $$