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Question-189350




Question Number 189350 by 073 last updated on 15/Mar/23
Answered by Rasheed.Sindhi last updated on 15/Mar/23
0.79^(−) =y (say)  100y=79.9^(−)      10y=7.9^(−)   100y−10y=72  y=((72)/(90))=(4/5)  y.x=((4/5)×x) ∈Z^+   x=5,10,15,...  Min(x)=5
$$\mathrm{0}.\mathrm{7}\overline {\mathrm{9}}={y}\:\left({say}\right) \\ $$$$\mathrm{100}{y}=\mathrm{79}.\overline {\mathrm{9}} \\ $$$$\:\:\:\mathrm{10}{y}=\mathrm{7}.\overline {\mathrm{9}} \\ $$$$\mathrm{100}{y}−\mathrm{10}{y}=\mathrm{72} \\ $$$${y}=\frac{\mathrm{72}}{\mathrm{90}}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$$${y}.{x}=\left(\frac{\mathrm{4}}{\mathrm{5}}×{x}\right)\:\in\mathbb{Z}^{+} \\ $$$${x}=\mathrm{5},\mathrm{10},\mathrm{15},… \\ $$$${Min}\left({x}\right)=\mathrm{5} \\ $$
Commented by 073 last updated on 15/Mar/23
nice solution
$$\mathrm{nice}\:\mathrm{solution} \\ $$

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