Question Number 58493 by Tawa1 last updated on 23/Apr/19
Answered by math1967 last updated on 24/Apr/19
$${At}\:\mathrm{2}.\mathrm{00}{pm}\:{distance}\:{between}\:\mathrm{2}{cars} \\ $$$$=\mathrm{915}\:−\mathrm{75}=\mathrm{840}{km} \\ $$$${time}\:{taken}\:{both}\:{meet}=\frac{\mathrm{840}}{\mathrm{75}+\mathrm{100}}=\mathrm{4}\frac{\mathrm{4}}{\mathrm{5}}{hr} \\ $$$$\mathrm{2}{pm}+\mathrm{4}{hr}\mathrm{48}{m}=\mathrm{6}:\mathrm{48}{pm} \\ $$
Commented by Tawa1 last updated on 24/Apr/19
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$