Question Number 189615 by Rupesh123 last updated on 19/Mar/23
Answered by HeferH last updated on 19/Mar/23
$$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{8x}}{\mathrm{3}\sqrt{\mathrm{5}}}−\frac{\mathrm{x}}{\:\sqrt{\mathrm{5}}} \\ $$$$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{5x}}{\mathrm{3}\sqrt{\mathrm{5}}} \\ $$$$\:\mathrm{48}\sqrt{\mathrm{5}}\:−\:\mathrm{15x}\:=\:\mathrm{5x} \\ $$$$\:\mathrm{x}\:=\:\frac{\mathrm{48}\sqrt{\mathrm{5}}}{\mathrm{20}} \\ $$$$\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{48}\centerdot\mathrm{5}}{\mathrm{20}}\:=\frac{\mathrm{48}}{\mathrm{4}}\:=\:\mathrm{12}\: \\ $$
Commented by HeferH last updated on 19/Mar/23
Commented by Rupesh123 last updated on 19/Mar/23
Excellent!
Commented by Rupesh123 last updated on 19/Mar/23
Excellent!