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Question-124376




Question Number 124376 by bemath last updated on 02/Dec/20
Answered by liberty last updated on 02/Dec/20
n(A)= C_1 ^( 10)  = 10  n(S) = C _2^(20)  = ((20×19)/(2×1)) = 190   p(A) = ((10)/(190)) = (1/(19)).
$${n}\left({A}\right)=\:{C}_{\mathrm{1}} ^{\:\mathrm{10}} \:=\:\mathrm{10} \\ $$$${n}\left({S}\right)\:=\:{C}\:_{\mathrm{2}} ^{\mathrm{20}} \:=\:\frac{\mathrm{20}×\mathrm{19}}{\mathrm{2}×\mathrm{1}}\:=\:\mathrm{190}\: \\ $$$${p}\left({A}\right)\:=\:\frac{\mathrm{10}}{\mathrm{190}}\:=\:\frac{\mathrm{1}}{\mathrm{19}}. \\ $$

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