Question Number 190198 by 073 last updated on 29/Mar/23
Answered by Rasheed.Sindhi last updated on 29/Mar/23
$$\mathrm{A}\in\mathbb{R}\Rightarrow \\ $$$$\mathrm{2}{x}−\mathrm{3}\geqslant\mathrm{0}\:\wedge\:\mathrm{3}−\mathrm{2}{x}\geqslant\mathrm{0} \\ $$$$\:\:{x}\geqslant\frac{\mathrm{3}}{\mathrm{2}}\:\wedge\:{x}\leqslant\frac{\mathrm{3}}{\mathrm{2}}\:\Rightarrow{x}=\frac{\mathrm{3}}{\mathrm{2}}\notin\mathbb{Z} \\ $$$$\mathrm{A}=\frac{\mathrm{4}\left(\frac{\mathrm{3}}{\mathrm{2}}\right)^{\mathrm{2}} +\mathrm{3}+\mathrm{0}+\mathrm{0}}{\mathrm{2}\left(\frac{\mathrm{3}}{\mathrm{2}}\right)}=\frac{\mathrm{9}+\mathrm{3}}{\mathrm{3}}=\mathrm{4} \\ $$
Commented by 073 last updated on 29/Mar/23
$$\mathrm{nice}\:\mathrm{solution} \\ $$